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<?php

$query = dbquery("SELECT SQL_NO_CACHE distinct user_two_id FROM messenger_friendships WHERE user_one_id = '" .USER_ID. "' GROUP by user_two_id");

$i = 0;

while($friends = @mysql_fetch_array($query))

{

$getfriend = dbquery("SELECT SQL_NO_CACHE distinct id,username,online FROM users WHERE id ='".$friends['user_two_id']."' AND online = '1' GROUP BY id LIMIT 1");

if(mysql_num_rows($getfriend) > 0)

{

$i++;

if($i == 1)

{

echo '';

}

$friend = @mysql_fetch_array($getfriend);

$friendname = $friend['username'];

echo htmlspecialchars($friend['username']).'</a>, ';

}

}

if($i > 0)

echo '</br>';

?>

Навыки: Графический дизайн, HTML, MySQL, PHP, Дизайн сайтов

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О работодателе:
( 0 отзыв(-а, -ов) ) United States

ID проекта: #6804440

6 фрилансеров(-а) готовы выполнить эту работу в среднем за $25

rinsadsl

Hi there I can make it fast. Interested on this job. Looking forward to hear from you. Thanks Rinsad

$24 USD за 1 день
(1026 отзывов(-а))
8.7
sprextech

----------------------------------------------------------Please Consider on My BID---------------------------------------------------Dear Sir/Madam, We are already read your project description & fully understand this Больше

$28 USD за 0 дней(-я)
(314 отзывов(-а))
7.6
NayaPakistan

A proposal has not yet been provided

$15 USD за 1 день
(249 отзывов(-а))
6.5
caneadysl

Hi sir, Requirement is clear Provide the sample database to debug the existing code. I am a master of php more than 11 years now. PM me for getting touch

$30 USD за 1 день
(56 отзывов(-а))
5.8
santanu1122

---------------------------------------------------------------------------- what is this.. what do u want?? -----------------------------------------

$25 USD за 0 дней(-я)
(37 отзывов(-а))
5.4
wajamil56

A proposal has not yet been provided

$25 USD за 0 дней(-я)
(3 отзывов(-а))
1.0