Check and load any file dynamically -- 2

I need a script/solution to use in my website, that allow to:

- check if file is already loaded (css, js, php, html, img, etc.)

- if file is loaded then it is used and avoid duplicate loading

- if file is not loaded the script check if cache exist and load file from cache

- if cache doesn't exist, the script load the file from the specified source and create cache

- project must be based on php and/or jquery

- instruction on how to use the provided code for load every file is needed

- i prefer who can start immediatelly

- I expect 1-2 hours work is enough

- Note: there is already code in the internet for check and load css and js files dynamically

[url removed, login to view]

- the solution must work for the followig cases:

a) js files


<script type="text/javascript" src="[url removed, login to view]"></script>

<script src="/js/[url removed, login to view]" language="javascript"></script>

b) css files


<link rel="stylesheet" href="/desk/top/[url removed, login to view]" type="text/css" media="screen"/>

c) img and video files

d) php included

Example: require_once($_SERVER['DOCUMENT_ROOT']."/[url removed, login to view]");

e) php loaded via ajax


<script type="text/javascript">

$(document).ready(function() {

$('.top_service a').load('/desk/top/top_service/[url removed, login to view]');



f) php or other files loaded via iframe (if possible)


<iframe id="main_iframe" src="/desk/center/[url removed, login to view]" width="56%" frameborder="0" scrolling="no" style="position:fixed; bottom:23px; height:80vh; background-color:#00CC00"></iframe>

g) php or other files loaded via ajax into iframe (if possible)



var vals = $(this).find('option:selected').val();


$('iframe').attr('src','/desk/center/scrollnav/[url removed, login to view]'+$(this).attr('id')+'&b='+vals);


Навыки: jQuery / Prototype, PHP

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О работодателе:
( 58 отзыв(-а, -ов) ) Coimbra, Portugal

ID проекта: #7899109



Hi, I will do it. But I need some clarification on it. Thanks & Regards, Dinakaran

$50 USD за 1 день
(7 отзывов(-а))

3 фрилансеров(-а) готовы выполнить эту работу в среднем за $52


Hi. I understand your requirements and I can complete this task for you. I can create the php code for this. Thanks!

$55 USD за 1 день
(19 отзывов(-а))

A proposal has not yet been provided

$50 USD за 1 день
(4 отзывов(-а))